0=30x^2/3-2x

Solution for 0=30x^2/3-2x equation:

0=30x^2/3-2x

We move all terms to the left:

0-(30x^2/3-2x)=0


Domain of the equation: 3-2x)!=0

We move all terms containing x to the left, all other terms to the right

-2x)!=-3

x!=-3/1

x!=-3

x∈R


We add all the numbers together, and all the variables

-(30x^2/3-2x)=0

We get rid of parentheses

-30x^2/3+2x=0

We multiply all the terms by the denominator


-30x^2+2x*3=0

Wy multiply elements

-30x^2+6x=0

a = -30; b = 6; c = 0;
Δ = b2-4ac
Δ = 62-4·(-30)·0
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{36}=6$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-6}{2*-30}=\frac{-12}{-60}
=1/5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+6}{2*-30}=\frac{0}{-60}
=0
$